Giải Bài 13 trang 13 sách bài tập toán 7 tập 1 - Cánh diều

Đề bài

Tính một cách hợp lí:

a) \(\dfrac{{ - 3}}{{11}} + 0,35 - \dfrac{8}{{11}}\);                     

b) \(\dfrac{9}{{19}} - 1,251 + \dfrac{{10}}{{19}} + 1,251\);

c) \( - 8.\dfrac{{24}}{7}.0,125\);                                                    

d) \(0,25.\dfrac{7}{{15}} - \dfrac{1}{4}.\dfrac{{ - 8}}{{15}} + 2,75\).

Lời giải chi tiết

a) \(\dfrac{{ - 3}}{{11}} + 0,35 - \dfrac{8}{{11}} = \left( {\dfrac{{ - 3}}{{11}} - \dfrac{8}{{11}}} \right) + 0,35 = \dfrac{{ - 11}}{{11}} + 0,35 =  - 1 + 0,35 =  - 0,65\);                                           

b) \(\dfrac{9}{{19}} - 1,251 + \dfrac{{10}}{{19}} + 1,251 = \left( {\dfrac{9}{{19}} + \dfrac{{10}}{{19}}} \right) + \left( { - 1,251 + 1,251} \right) = 1 + 0 = 1\);

c) \( - 8.\dfrac{{24}}{7}.0,125 =  - 8.\dfrac{{24}}{7}.\dfrac{1}{8} = \left( { - 8.\dfrac{1}{8}} \right).\dfrac{{24}}{7} =  - 1.\dfrac{{24}}{7} = \dfrac{{ - 24}}{7}\);                                 

d) \(\begin{array}{l}0,25.\dfrac{7}{{15}} - \dfrac{1}{4}.\dfrac{{ - 8}}{{15}} + 2,75 = \dfrac{1}{4}.\dfrac{7}{{15}} + \dfrac{1}{4}.\dfrac{8}{{15}} + \dfrac{{11}}{4}\\{\rm{                                    }} = \dfrac{1}{4}.\left( {\dfrac{7}{{15}} + \dfrac{8}{{15}}} \right) + \dfrac{{11}}{4} = \dfrac{1}{4}.1 + \dfrac{{11}}{4}\\{\rm{                                      = }}\dfrac{1}{4} + \dfrac{{11}}{4} = \dfrac{{12}}{4} = 3\end{array}\).