Bài 112 trang 31 SBT toán 6 tập 2

Đề bài

Tính 

a) \(\displaystyle 6{3 \over 8} + 5{1 \over 2}\)      b) \(\displaystyle 5{3 \over 7} - 2{3 \over 7}\)

c) \(\displaystyle - 5{1 \over 7} + 3{2 \over 5}\)    d) \(\displaystyle - 2{1 \over 3} - 1{2 \over 7}\)

Lời giải chi tiết

a) \(\displaystyle {\rm{}}6{3 \over 8} + 5{1 \over 2} = \left( {6 + 5} \right) + \left( {{3 \over 8} + {1 \over 2}} \right) \)

\(\displaystyle = 11 + \left( {{3 \over 8} + {4 \over 8}} \right) = 11 + {7 \over 8} = 11{7 \over 8}.\) 

b) \(\displaystyle 5{3 \over 7} - 2{3 \over 7} = \left( {5 - 2} \right) + \left( {{3 \over 7} - {3 \over 7}} \right) \)\(\displaystyle= 3.\) 

c) \(\displaystyle  - 5{1 \over 7} + 3{2 \over 5} \)\(\displaystyle= \left( { - 5 + 3} \right) + \left( {{{ - 1} \over 7} + {2 \over 5}} \right) \)
\(\displaystyle = - 2 + \left( {{{ - 5} \over {35}} + {{14} \over {35}}} \right) = - 2 + {9 \over {35}} \)
\(\displaystyle =  {{-70} \over {35}} + {9 \over {35}} = {-61 \over {35}} = - 1{{26} \over {35}}. \)

d) \(\displaystyle  - 2{1 \over 3} - 1{2 \over 7} = - \left( {2{1 \over 3} + 1{2 \over 7}} \right) \)
\(\displaystyle = - \left[ {\left( {2 + 1} \right) + \left( {{1 \over 3} + {2 \over 7}} \right)} \right] \) 
\(\displaystyle= - \left[ {3 + \left( {{7 \over {21}} + {6 \over {21}}} \right)} \right] = - 3{{13} \over {21}}. \)