Bài 2 trang 11 SGK Toán 5

Đề bài

Tính:

a) \( \dfrac{9}{10}\times\dfrac{5}{6}\) ;                          b) \( \dfrac{6}{25}:\dfrac{21}{20}\);

c) \( \dfrac{40}{7}\times\dfrac{14}{5}\) ;                        d) \( \dfrac{17}{13}:\dfrac{51}{26}\).

Lời giải chi tiết

a) \( \dfrac{9}{10} \times \dfrac{5}{6} = \dfrac{9 \times 5}{10\times 6}\) \(=\dfrac{3\times 3\times 5}{2\times 5 \times 2 \times 3}=\dfrac{3}{4}\) ;

b) \( \displaystyle \dfrac{6}{25}:\dfrac{21}{20} = \dfrac{6}{25}\times \dfrac{20}{21}={{6 \times 20} \over {25 \times 21}}\) \( =\dfrac{3\times 2 \times 4 \times5}{5 \times 5 \times 7 \times3}\)\(=\dfrac{8}{35}\) ;

c) \( \dfrac{40}{7} \times \dfrac{14}{5} =\dfrac{40 \times 14}{7\times 5}=\dfrac{ 5 \times 8 \times 2 \times 7}{5\times7}=16\) ; 

d) \(  \displaystyle \dfrac{17}{13}:\dfrac{51}{26}= \dfrac{17}{13}\times \dfrac{26}{51}={{17 \times 26} \over {13 \times 51}}\)\( =\dfrac{17 \times 2 \times 13}{13 \times 3 \times 17}=\dfrac{2}{3}\) .